Home made auxilliary battery question

hi guys, i'm confused.
Power wise everything operates to specs on my pretty new AAO.
However, the internal battery (the 2.5hr one) is 12.5 DC volts yet the ac power
supply is 19 DC volts. Will someone please explain this.
When i plug in my little home made 19 volt DC battery pack into the external
power jack I believe the puter is still operating on the internal 12 volt DC battery AND
the battery lamp blinks? I see no voltage drop accross my little battery pack.
Maybe if i remove the 12.5 volt battery it will work? I haven't done this
because i'm afraid of the unknowns here and need some answers before I
mess up my pretty new puter.
Thanks for any help
Amber

 

If your external battery works, you should see the power LED light up as if the netbook is plugged in.

How close is the voltage on your battery to that of the power adapter?

 

Yes, power lamp at upper right lights, but the battery lamp front left blinks and dosen't
when operating normaly. My lil battery pack is 20.5 volts, but I wish I knew how much
over voltage was safe. I would hope for 300 smackers over voltage protection was built
into the thing. I can see no reason why this battery pack wouldn't work since its quite
common to convert 12VDC from an auto battery to 19VDC and plug it into the same power
jack the external supply plugs into. That power supply that comes with the puter does
alot for its size and never gets hot, powers puter AND charges the internal battery at
same time.
Amber

 

Is your plug the right one ? I guess, the current doesn't flow in your case.

 

Must say I'm surprised this question is going no where here.
Oh well, live and learn they say..............
adios
Amber

 

Have you checked the voltage when the aux battery pack is plugged to the computer. While charging, 2-3 amps at 19 volts is pretty common which would explain why your aux battery can't keep the voltage if the amperage rating isn't enough...

 

I removed the ((TEN VOLT)) internal battery.
Plugged in my battery pack, voltage read ((NINETEEN VOLTS DC)).
With START BUTTON pushed voltage dropped .5 volts to 18.5 volts DC.
In my opinion this puter should have fired up but didn't. Unfortunately
my questions regarding the voltages used in this puter and WHY they are used
are not well understood. Like why is the internal battery ((TEN VOLTS DC))
and the AC to DC power supply is ((NINETEEN VOLTS DC)). That deserves
somekind of explanation, as does the "why dosen't it like my
((NINETEEN VOLT DC)) battery pack. I should have made some attempt
to contact Acer directly, maybe now I will. Once again, I consider this an
excellent product for what it is.
Amber

 

The voltage into the unit has to be higher than the voltage of the battery to charge it. Charging for the lithium battery needs at least 14 volts as a typical lithium cell is 4.1 volts at full charge, 12.4 volts for three cells in series. The 18 volts can easily charge and power the net-book without needing too much amperage.

If you are trying to hook up your 18 volt battery directly to the 3 cell lithium battery connector, which I am not sure you're doing, it won't work. There are I think 4 leads to the battery which there is also some components in the battery for charging and to ensure the net-book has the correct battery for it. I think all laptops/net-books have this circuitry in their batteries for charging and communication. Even my PSP has an ID number the battery has to give for it to work right.

If you are using your 18 volt battery into the charging connector where the AC adapter usually goes, then I am not sure why it isn't working. I've used an HP 12v to 18v car adapter on my AA1 without any problems...

 

My guess is your battery pack is not within voltae range of the computer's parameters (under load).
I use a non Acer supply quite often and it works fine. Also, and I can't really imagine this is a problem, but make sure the polarity is correct. Inner positive shell negative.
Finally, the reason supply voltage is higher than battery voltage is that it is easy to regulate the actual working voltage from higher to lower.